Two coins are tossed simultaneously. What is the probability of getting at least one tail?


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Answer:

^@\dfrac { 3 } { 4 } ^@

Step by Step Explanation:
  1. When two coins are tossed simultaneously, all possible outcomes are ^@ HH, HT, TH, TT^@.

    The total number of all possible outcomes = ^@4^@.

  2. Let ^@E^@ be the event of getting at least one tail.

    Therefore, ^@E^@ is the event of getting ^@1^@ tail or ^@2^@ tails.

    So, the favourable outcomes from ^@ HH, HT, TH, TT^@ are ^@HT, TH^@ and ^@TT^@.

    Number of favourable outcomes = 3. @^ \begin{aligned} \therefore \space P(\text{getting at least one tail}) = P(E) = \dfrac { 3 } { 4 }. \end{aligned} @^
  3. Therefore, the probabilty of getting at least one tail is ^@\dfrac { 3 } { 4 } ^@.

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